头歌平台云盘算实验
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Hive综合应用案例——用户学历查询
1 查询每一个用户从出生到现在的总天数
---------- 禁止修改 ----------
drop database if exists mydb cascade;
---------- 禁止修改 ----------
---------- begin ----------
---创建mydb数据库
create database if not exists mydb;
---使用mydb数据库
use mydb;
---创建表user
create table usertab(
id string,
sex string,
time string,
education string,
occupation string,
income string,
area string,
desired_area string,
city_countryside string
)
row format delimited fields terminated by ',';
---导入数据：/root/data.txt
load data local inpath '/root/data.txt' into table usertab;
--查询每一个用户从出生到2019-06-10的总天数
select id, datediff('2019-06-10',regexp_replace(time, '/', '-')) from usertab;
2 同一个地区雷同的教育程度的最高收入
---------- 禁止修改 ----------
drop database if exists mydb cascade;
---------- 禁止修改 ----------
---------- begin ----------
--创建mydb数据库
create database if not exists mydb;
---使用mydb数据库
use mydb;
---创建表user
create table usertab1(
id int,
sex string,
time string,
education string,
occupation string,
income string,
area string,
desired_area string,
city_countryside string
)
row format delimited fields terminated by ',';
---导入数据：/root/data.txt
load data local inpath '/root/data1.txt' into table usertab1;
--同一个地区相同的教育程度的最高收入
select area,education,income
from(
select area,education,income,
row_number() over(
partition by area, education order by income desc
) as t1
from usertab1
) as t2
where t2.t1 = 1;
---------- end ----------
3 统计各级学历所占总人数百分比
---------- 禁止修改 ----------
drop database if exists mydb cascade;
set hive.mapred.mode=nonstrict;
---------- 禁止修改 ----------
---------- begin ----------
--创建mydb数据库
create database if not exists mydb;
---使用mydb数据库
use mydb;
---创建表user
create table usertab2(
id int,
sex string,
time string,
education string,
occupation string,
income string,
area string,
desired_area string,
city_countryside string
)
row format delimited fields terminated by ',';
---导入数据：/root/data.txt
load data local inpath '/root/data.txt' into table usertab2;
--统计各级学历所占总人数百分比(对结果保留两位小数)
select concat(round(t1.cnted * 100 / t2.cnt, 2),'%'), t1.education
from
(
select count(*) as cnted,education
from usertab2
group by education
) as t1,
(
select count(*) as cnt from usertab2
) as t2
order by t1.education;
---------- end ----------
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