红包分配问题 - ToB企服应用市场:ToB评测及商务社交产业平台

1 public class Test2 {
2 public static void main(String[] args) {
3 System.out.println(Arrays.toString(luckyMoney("150.01", 10)));
4 }
5
6 public static BigDecimal[] luckyMoney(String money,int n){//红包金额/元，红包个数
7 double money1= 0;
8 try {
9 money1 = Double.parseDouble(money);
10 } catch (NumberFormatException e) {
11 System.out.println("输入金额错误！");
12 e.printStackTrace();
13 return null;
14 }
15 //System.out.println(money1);
16 int total=(int) (money1*100);//因为人民币的金额最小挡位为分，可以先将红包的金额转化为以分为单位，转化成整型
17 int rest=total-n;//红包剩余金额，因为每个红包的最小金额为1分，所以可以把每个红包的初始量设为1分
18 int[] luckMoney=new int[n];
19 Random r = new Random();
20 for (int i = 0; i < luckMoney.length; i++) {
21 if (i==luckMoney.length-1){//最后一个红包金额等于红包金额的最后剩余量+1分
22 luckMoney[luckMoney.length-1]=1+rest;
23 break;
24 }
25 if (rest>0){
26 int temp=r.nextInt(rest+1);//
27 luckMoney[i]=1+temp;
28 rest-=temp;
29 }else {//红包剩余金额已经分配完了，剩余红包的金额都为1分
30 luckMoney[i]=1;
31 }
32 }
33 BigDecimal[] luckMoney1=new BigDecimal[n];//这里用BigDecimal数组来记录红包的金额，因为BigDecimal进行计算时不会丢失精度
34 //BigDecimal sum = new BigDecimal("0");
35 for (int i = 0; i < luckMoney.length; i++) {
36 BigDecimal a = new BigDecimal(""+luckMoney[i]);
37 BigDecimal b = new BigDecimal("100");
38 luckMoney1[i]= a.divide(b,2,BigDecimal.ROUND_HALF_UP);//转化以元为单位时，除以100，应保留两位小数
39 sum=sum.add(luckMoney1[i]);
40 }
41 //System.out.println(sum);
42 return luckMoney1;
43 }
44 }

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[16.50, 19.03, 64.12, 30.99, 8.96, 1.57, 2.10, 5.22, 0.04, 1.48]

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[17.18, 112.52, 5.46, 0.97, 6.43, 3.26, 1.88, 1.27, 0.95, 0.09]

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[82.38, 23.82, 14.27, 18.89, 4.31, 1.34, 4.16, 0.34, 0.12, 0.38]

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1 public class Test2 {
2 public static void main(String[] args) {
3 System.out.println(Arrays.toString(luckyMoney("150.01", 10)));
4 }
5
6 public static BigDecimal[] luckyMoney(String money,int n){
7 double money1= 0;
8 try {
9 money1 = Double.parseDouble(money);
10 } catch (NumberFormatException e) {
11 System.out.println("输入金额错误！");
12 e.printStackTrace();
13 return null;
14 }
15 System.out.println(money1);
16 int total=(int) (money1*100);
17 int rest=total-n;
18 int restNum=n;//剩余红包个数
19 int[] luckMoney=new int[n];
20 Random r = new Random();
21 for (int i = 0; i < luckMoney.length; i++) {
22 if (i==luckMoney.length-1){
23 luckMoney[luckMoney.length-1]=1+rest;
24 break;
25 }
26 if (rest>0){
27 int temp=r.nextInt(rest*2/restNum+1);//修改处
28 restNum--;
29 luckMoney[i]=1+temp;
30 rest-=temp;
31 }else {
32 luckMoney[i]=1;
33 }
34 }
35 BigDecimal[] luckMoney1=new BigDecimal[n];
36 BigDecimal sum = new BigDecimal("0");
37 for (int i = 0; i < luckMoney.length; i++) {
38 BigDecimal a = new BigDecimal(""+luckMoney[i]);
39 BigDecimal b = new BigDecimal("100");
40 luckMoney1[i]= a.divide(b,2,BigDecimal.ROUND_HALF_UP);
41 sum=sum.add(luckMoney1[i]);
42 }
43 System.out.println(sum);
44 return luckMoney1;
45 }
46 }

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[7.21, 30.82, 26.08, 21.54, 7.81, 22.19, 9.72, 15.15, 3.89, 5.60]

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