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题目:329. 矩阵中的最长递增路径 - 力扣(LeetCode)
数据规模很小,排序就够了
- struct Node {
- int x;
- int y;
- int val;
- Node* up = nullptr;
- Node* down = nullptr;
- Node* left = nullptr;
- Node* right = nullptr;
- int length = 0;
- Node(int _x, int _y, int _v) {
- x = _x;
- y = _y;
- val = _v;
- }
- };
- bool myComp(Node* a, Node* b) {
- return a->val < b->val;
- }
- class Solution {
- public:
- int longestIncreasingPath(vector<vector<int>>& matrix) {
- vector<Node*> arr;
- int upIdx, leftIdx;
- for (int i = 0; i < matrix.size(); i++) {
- vector<int>& t = matrix[i];
- for (int j = 0; j < t.size(); j++) {
- Node* node = new Node(i, j, t[j]);
- arr.push_back(node);
- if (i > 0) {
- upIdx = (i - 1) * t.size() + j;
- node->up = arr[upIdx];
- arr[upIdx]->down = node;
- }
- if (j > 0) {
- leftIdx = i * t.size() + j - 1;
- node->left = arr[leftIdx];
- arr[leftIdx]->right = node;
- }
- }
- }
- sort(arr.begin(), arr.end(), myComp);
- int max;
- int ret = 1;
- for (int i = 0; i < arr.size(); i++) {
- Node* node = arr[i];
- max = 0;
- if (node->left && node->left->val < node->val && node->left->length > max) {
- max = node->left->length;
- }
- if (node->right && node->right->val < node->val && node->right->length > max) {
- max = node->right->length;
- }
- if (node->up && node->up->val < node->val && node->up->length > max) {
- max = node->up->length;
- }
- if (node->down && node->down->val < node->val && node->down->length > max) {
- max = node->down->length;
- }
- node->length = max + 1;
- if (node->length > ret) {
- ret = node->length;
- }
- }
- return ret;
- }
- };
复制代码
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